49r^2+4=53

Solution for 49r^2+4=53 equation:

49r^2+4=53

We move all terms to the left:

49r^2+4-(53)=0

We add all the numbers together, and all the variables

49r^2-49=0

a = 49; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·49·(-49)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-98}{2*49}=\frac{-98}{98}
=-1
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+98}{2*49}=\frac{98}{98}
=1
$